100(1-1/k^2)=89

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Solution for 100(1-1/k^2)=89 equation: 


D( k )

k^2 = 0

k^2 = 0

k^2 = 0

1*k^2 = 0 // : 1

k^2 = 0

k = 0

k in (-oo:0) U (0:+oo)

100*(1-(1/(k^2))) = 89 // - 89

100*(1-(1/(k^2)))-89 = 0

100*(1-k^-2)-89 = 0

100*(1-k^-2)-89 = 0

11-100*k^-2 = 0

11-100*k^-2 = 0

-100*k^-2 = -11 // : -100

k^-2 = 11/100

-2 < 0

1/(k^2) = 11/100 // * k^2

1 = 11/100*k^2 // : 11/100

100/11 = k^2

k^2 = 100/11 // ^ 1/2

abs(k) = (100/11)^(1/2)

k = (100/11)^(1/2) or k = -(100/11)^(1/2)

k in { (100/11)^(1/2), -(100/11)^(1/2) }

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